Resonance in a driven string
A taut string of length L and mass m has its right end fixed
while the left end is driven and moves harmonically:
y(t,0)
= A cos Ωt,
y(t,L) = 0.
The simulation computes the steady state solution and can be used to
check how resonance happens when the driving frequancy is (nearly) one
of the normal frequencies, i.e. , one of the frequencies of the standing
waves that may appear in the string when both ends are fixed.
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The unit length is L and the unit time L/v, where v
= √(TL/m) is the phase velocity of transverse waves
propagating along the string, whete the tension is T.
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You can select below the dimensionless frequency of the driving force, ω
≡ Ω L/π v, and its amplitude A,
as well as the number of discretization points N and the time
interval between animation frames Δt.
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To get information on an element, put over it the mouse pointer to see
the corresponding tooltip.
Activities
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Try in the wave equation of the vibrating string a solution in the
form y(t,x) = f(x) cos Ωt
and show that in order to satisfy the boundary conditions (which now
read f(0) = A, f(L) = 0) one has to choose
f(x)
= A sin k(L-x)/sin kL,
where k
= Ω/v.
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Discuss in which cases resonance will appear.
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Why is unbounded this steady state solution when resonance appear?
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Use the simulation to check the discussion above.
This is an English translation of the Basque original for a course
on mechanics, oscillations and waves.
It requires Java
1.5 or newer and was created by Juan
M. Aguirregabiria with Easy
Java Simulations (Ejs) by Francisco
Esquembre. I thank Wolfgang Christian and Francisco Esquembre for
their help.